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  • $\begingroup$ I think I don't understand anything from this answer xD. I don't know what spectra are (my topology knowledge is not great), and I don't know anything about $\infty$-categories either. $\endgroup$ Commented Sep 20 at 10:15
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    $\begingroup$ Let me reinforce Neil's answer here with another example. If you ind complete the small stable module category of a finite group as a triangulated category, you get the big stable module category modulo phantoms, which is (probably) not triangulated, and not really what you want. However, if you regard it as a stable infinity category and ind complete, you get the big stable module category that you wanted, as a stable infinity category. An intermediate solution is to use differential graded categories, and this works well, but comes with its own problems. $\endgroup$ Commented Sep 20 at 10:31
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    $\begingroup$ Now I am confused: Isn't the homotopy category of a stable $\infty$-category triangulated? I guess, the Ind-completion does not commute with taking the homotopy category? $\endgroup$ Commented Sep 20 at 11:31
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    $\begingroup$ @UlrichPennig Yes it is; no it doesn't. $\endgroup$ Commented Sep 20 at 11:37
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    $\begingroup$ There is a short argument in Remark 5.9 of math.uni-bielefeld.de/~hkrause/completion.pdf, which I believe shows that the ind-completion (in the triangulated sense) of the stable module category is not triangulated if the Sylow p-subgroup of $G$ is not cyclic. $\endgroup$
    – Drew Heard
    Commented Sep 24 at 17:21