We can look on the permutohedron as a kind of "embedding" of the Cayley graph of $S_n$ to the Euclidean space. (That Cayley graph is constructed by the standard generators, i.e. transpositions $(i,i+1)$ ).
Any graph is naturally a metric space – with the distance between nodes defined as length of the shortest path between the two nodes. On the other hand we have standard Euclidean distance in $\mathbb{R}^n$. We might hope that for good "embeddings" graph metric is not that much distorted by the embeddings.
The permutohedron embedding is kind of "very good" appearing in many fields of mathematics, so natural to ask:
Question 1: Is there any kind of results that suggests that the permutohedron in in some sense minimal possible distortion embedding of that particular $S_n$ Cayley graph ? (Or may be opposite – there are other embeddings which have less distortion ?) Also we might require embedding to be symmetric (i.e. natural action of $S_n$ on $\mathbb{R}^n$ by permutation matrices preserves graph).
We can ask similar questions for the truncated cube, also for some other polytopes from the beautiful collection at https://weddslist.com/groups/cayley-plat/index.html (but here are some small groups ). And for any other polytope would appear in the answers to the question: What Cayley graphs arise as nodes+edges from "nice" polytopes and when are these polytopes convex?
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Motivation comes from the machine-learning. Embeddings of everything texts/images/proteins... are highly important in ML. It would be nice to understand more mathematical properties which might distinguish "good embeddings" at least for graphs. Cayley graphs may serve as a kind of model example to understand the general picture. Related question: What Cayley graphs arise as nodes+edges from "nice" polytopes and when are these polytopes convex?
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There are results by T.Tao on distortion, seems to me they are related to similar question for Cayley graph of the Heisenberg group $H_3(Z)$, but in some sense about the continous limit of the graph metric, but not sure at the moment.